Difference between revisions of "1987 AJHSME Problems/Problem 4"

(New page: ==Problems== Martians measure angles in clerts. There are <math>500</math> clerts in a full circle. How many clerts are there in a right angle? <math>\text{(A)}\ 90 \qquad \text{(B)}\ ...)
 
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==Solution==
 
==Solution==
  
{{Solution}}
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The right angle is <math>1/4</math> of the circle, hence it contains <math>500/4=\boxed{125}</math> clerts.
  
 
==See Also==
 
==See Also==
  
 
[[1987 AJHSME Problems]]
 
[[1987 AJHSME Problems]]

Revision as of 13:42, 29 January 2009

Problems

Martians measure angles in clerts. There are $500$ clerts in a full circle. How many clerts are there in a right angle?

$\text{(A)}\ 90 \qquad \text{(B)}\ 100 \qquad \text{(C)}\ 125 \qquad \text{(D)}\ 180 \qquad \text{(E)}\ 250$

Solution

The right angle is $1/4$ of the circle, hence it contains $500/4=\boxed{125}$ clerts.

See Also

1987 AJHSME Problems