Difference between revisions of "2004 AMC 10B Problems/Problem 1"
(New page: Start from Row 12 to row 22. There are 11 rows in total. 33*11 = 363; (C)) |
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− | + | ==Problem== | |
− | 33 | + | Each row of the Misty Moon Amphitheater has 33 seats. Rows 12 through 22 are reserved for a youth club. How many seats are reserved for this club? |
+ | |||
+ | <math> \mathrm{(A) \ } 297 \qquad \mathrm{(B) \ } 330\qquad \mathrm{(C) \ } 363\qquad \mathrm{(D) \ } 396\qquad \mathrm{(E) \ } 726 </math> | ||
+ | |||
+ | ==Solution== | ||
+ | There are <math>22-12+1=11</math> rows of <math>33</math> seats, giving <math>11\times 33=\boxed{363}</math> seats. | ||
+ | |||
+ | == See also == | ||
+ | |||
+ | {{AMC10 box|year=2004|ab=B|before=First Question|num-a=2}} |
Revision as of 12:26, 7 February 2009
Problem
Each row of the Misty Moon Amphitheater has 33 seats. Rows 12 through 22 are reserved for a youth club. How many seats are reserved for this club?
Solution
There are rows of seats, giving seats.
See also
2004 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |