Difference between revisions of "Divisibility rules/Rule for 17 proof"
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<math>5n_0-k\equiv 5n_0+16k\equiv 5n_0+33k\equiv 5n_0+50k\equiv n_0+10k</math>, which is our original number. | <math>5n_0-k\equiv 5n_0+16k\equiv 5n_0+33k\equiv 5n_0+50k\equiv n_0+10k</math>, which is our original number. | ||
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+ | ''[[Divisibility_rules#Divisibility_Rule_for_17 | Back to main article]]'' |
Revision as of 13:58, 21 July 2009
If the rule is (the opposite of the suggested rule , but that is proven in turn, and ) we know that :
, which is our original number.