Difference between revisions of "1975 USAMO Problems/Problem 4"
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Let E and F be the centers of the small and big circles, respectively, and r and R be their respective radii. | Let E and F be the centers of the small and big circles, respectively, and r and R be their respective radii. | ||
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Draw a circle with center P and radius PE to cut the radius PF at H. Draw the line parallel to EH passing through P. This line meets the small and big circles at A and B, respectively. | Draw a circle with center P and radius PE to cut the radius PF at H. Draw the line parallel to EH passing through P. This line meets the small and big circles at A and B, respectively. | ||
− | + | Solution with graph posted at | |
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+ | http://www.cut-the-knot.org/wiki-math/index.php?n=MathematicalOlympiads.USA1975Problem4 | ||
==See also== | ==See also== |
Revision as of 15:48, 4 February 2010
Problem
Two given circles intersect in two points and . Show how to construct a segment passing through and terminating on the two circles such that is a maximum.
by Vo Duc Dien
Let E and F be the centers of the small and big circles, respectively, and r and R be their respective radii.
Let M and N be the feet of E and F to AB, and α = ∠APE and ε = ∠BPF
We have:
AP × PB = 2r cosα × 2R cosε = 4 rR cosα cosε
AP × PB is maximum when the product cosα cosε is a maximum.
We have cosα cosε = ½ [cos(α + ε) + cos(α - ε)]
But α + ε = 180° - ∠EPF and is fixed, so is cos(α + ε)
So its maximum depends on cos(α - ε) which occurs when α = ε. To draw the line AB:
Draw a circle with center P and radius PE to cut the radius PF at H. Draw the line parallel to EH passing through P. This line meets the small and big circles at A and B, respectively.
Solution with graph posted at
http://www.cut-the-knot.org/wiki-math/index.php?n=MathematicalOlympiads.USA1975Problem4
See also
1975 USAMO (Problems • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 | ||
All USAMO Problems and Solutions |