Difference between revisions of "Hlder's inequality"
(Created page with 'The '''Hölder's Inequality,''' a generalization of the '''Cauchy-Schwarz inequality''', states that, For all <math>a_i, b_i > 0 , p,q > 0</math> such that <math>\frac {1}{p} \pl…') |
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The '''Hölder's Inequality,''' a generalization of the '''Cauchy-Schwarz inequality''', states that, | The '''Hölder's Inequality,''' a generalization of the '''Cauchy-Schwarz inequality''', states that, | ||
− | For all <math>a_i, b_i > 0 , p,q > 0</math> such that <math>\frac {1}{p} | + | For all <math>a_i, b_i > 0 , p,q > 0</math> such that <math>\frac {1}{p}+ \frac {1}{q} =1,</math> we have:<br> |
− | <math>\sum_{i | + | <math>\sum_{i =1}^n a_ib_i\leq \left(\sum_{i=1}^n a_i^p\right)^{\frac {1}{p}}\left(\sum _{i =1}^n b_i^q\right)^{\frac {1}{q}}.</math> |
<br> | <br> | ||
Letting <math>p=q=2</math> in this inequality leads to the Cauchy-Schwarz Inequality. | Letting <math>p=q=2</math> in this inequality leads to the Cauchy-Schwarz Inequality. |
Revision as of 03:51, 4 December 2010
The Hölder's Inequality, a generalization of the Cauchy-Schwarz inequality, states that,
For all such that we have:
Letting in this inequality leads to the Cauchy-Schwarz Inequality.
This can also be generalized further to sets of variables with a similar form.
Applications
1. Given we have,
2. Power-mean inequality: For and we have