Difference between revisions of "2010 AMC 10B Problems/Problem 12"
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| − | The minimum possible value occurs when <math>20%</math> of the students who originally answered "No." answer "Yes." In this case, <math>x=20</math> | + | The minimum possible value occurs when <math>20\%</math> of the students who originally answered "No." answer "Yes." In this case, <math>x=20</math> |
| − | The maximum possible value occurs when <math>30%</math> of the students who originally answered "Yes." answer "No." and the <math>50%</math> of the students who originally answered "No." answer "Yes." In this case, <math>x=50+30=80</math> | + | The maximum possible value occurs when <math>30\%</math> of the students who originally answered "Yes." answer "No." and the <math>50\%</math> of the students who originally answered "No." answer "Yes." In this case, <math>x=50+30=80</math> |
Subtract <math>80-20</math> to obtain an answer of <math>\boxed{\mathrm{(D)} 60}</math> | Subtract <math>80-20</math> to obtain an answer of <math>\boxed{\mathrm{(D)} 60}</math> | ||
Revision as of 14:06, 24 January 2011
The minimum possible value occurs when 
of the students who originally answered "No." answer "Yes." In this case, 
The maximum possible value occurs when 
of the students who originally answered "Yes." answer "No." and the 
of the students who originally answered "No." answer "Yes." In this case, 
Subtract 
to obtain an answer of 
