Difference between revisions of "2000 AMC 8 Problems/Problem 1"

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So, the answer is <math>\boxed{B}</math>
 
So, the answer is <math>\boxed{B}</math>
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{{AMC8 box|year=2000|before=First Question|num-a=2}}

Revision as of 12:28, 18 March 2011

Problem

Aunt Anna is $42$ years old. Caitlin is $5$ years younger than Brianna, and Brianna is half as old as Aunt Anna. How old is Caitlin?

$\mathrm{(A)}\ 15 \qquad \mathrm{(B)}\ 16 \qquad \mathrm{(C)}\ 17 \qquad \mathrm{(D)}\ 21 \qquad \mathrm{(E)}\ 37$

Solution

If Brianna is half as old as Aunt Anna, then Briana is $42/2$ years old, or $21$ years old.

If Caitlin is $5$ years younger than Briana, she is $21-5$ years old, or $16$.

So, the answer is $\boxed{B}$

2000 AMC 8 (ProblemsAnswer KeyResources)
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First Question
Followed by
Problem 2
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All AJHSME/AMC 8 Problems and Solutions