Difference between revisions of "Functional equation"

m (Functional Equations moved to Functional equation: removed unnecessary capitalization and made singular)
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===The Inverse of a Function===
 
===The Inverse of a Function===
  
The inverse of a function is a function that "undoes" a function.  For an example, consider the function: f(x)<math> = x^2 + 6</math>.  The function <math>g(x) = \sqrt{x-6}</math> has the property that <math>f(g(x)) = x</math>.  In this case <math>g</math> is called the inverse function.  Often the inverse of a function <math>f</math> is denoted by <math>f^{-1}</math>.
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The inverse of a function is a function that "undoes" a function.  For an example, consider the function: f(x)<math> = x^2 + 6</math>.  The function <math>g(x) = \sqrt{x-6}</math> has the property that <math>f(g(x)) = x</math>.  In this case, <math>g</math> is called the inverse function.  Often the inverse of a function <math>f</math> is denoted by <math>f^{-1}</math>.
  
 
==Intermediate Topics==
 
==Intermediate Topics==
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===Cyclic Functions===
 
===Cyclic Functions===
  
A cycylic function is a function <math>f(x)</math> that has the property that:
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A cyclic function is a function <math>f(x)</math> that has the property that:
  
 
<math>f(f(\cdots f(x) \cdots)) = x</math>
 
<math>f(f(\cdots f(x) \cdots)) = x</math>

Revision as of 13:29, 23 June 2006

Functional Equations are equations that involve functions. For an example, these are some examples of functional equations:

  • $f(x) + f\left(\frac1x\right) = 2x$
  • $g(x)^2 + 4g(x) + 4 = 8\sin{x}$

Introductory Topics

The Inverse of a Function

The inverse of a function is a function that "undoes" a function. For an example, consider the function: f(x)$= x^2 + 6$. The function $g(x) = \sqrt{x-6}$ has the property that $f(g(x)) = x$. In this case, $g$ is called the inverse function. Often the inverse of a function $f$ is denoted by $f^{-1}$.

Intermediate Topics

Cyclic Functions

A cyclic function is a function $f(x)$ that has the property that:

$f(f(\cdots f(x) \cdots)) = x$

A classic example of such a function is $f(x) = 1/x$ because $f(f(x)) = f(1/x) = f(x)$. Cyclic functions can significantly help in solving functional identities. Consider this problem:

Find $f(x)$ such that $3f(x) - 4f(1/x) = x^2$. In this functional equation, let $x=y$ and let $x = 1/y$. This yields two new equations:

$3f(y) - 4f\left(\frac1y\right) = y^2$

$3f\left(\frac1y\right)- 4f(y) = \frac1{y^2}$

Now, if we multiply the first equation by 3 and the second equation by 4, and substract the second equation from the first, we have:

$25f(y) = 3y^2 - \frac{4}{y^2}$

So clearly, $f(y) = \frac{3}{25}y^2 - \frac{4}{25y^2}$

See Also