Difference between revisions of "2004 AMC 10B Problems/Problem 1"
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==Solution== | ==Solution== | ||
| − | There are <math>22-12+1=11</math> rows of <math>33</math> seats, giving <math>11\times 33=\boxed{363}</math> seats. | + | There are <math>22-12+1=11</math> rows of <math>33</math> seats, giving <math>11\times 33=\boxed{(C) 363}</math> seats. |
== See also == | == See also == | ||
{{AMC10 box|year=2004|ab=B|before=First Question|num-a=2}} | {{AMC10 box|year=2004|ab=B|before=First Question|num-a=2}} | ||
Revision as of 18:37, 29 December 2011
Problem
Each row of the Misty Moon Amphitheater has 33 seats. Rows 12 through 22 are reserved for a youth club. How many seats are reserved for this club?
Solution
There are 
rows of 
seats, giving 
seats.
See also
| 2004 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
