Difference between revisions of "2010 AMC 8 Problems/Problem 10"

m (Solution to Problem 10.)
 
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The area of the the pizza is about 113.04 if pi is 3.14.
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==Problem==
The area of each pepperoni slice is about 3.14.
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Six pepperoni circles will exactly fit across the diameter of a <math>12</math>-inch pizza when placed. If a total of <math>24</math> circles of pepperoni are placed on this pizza without overlap, what fraction of the pizza is covered by pepperoni?
  
          ;<math>24*3.14=75.36</math>
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<math> \textbf{(A)}\ \frac 12 \qquad\textbf{(B)}\ \frac 23 \qquad\textbf{(C)}\ \frac 34 \qquad\textbf{(D)}\ \frac 56 \qquad\textbf{(E)}\ \frac 78 </math>
 
 
        ;<math>75.36/113.04=2/3=B</math>
 

Revision as of 23:33, 3 November 2012

Problem

Six pepperoni circles will exactly fit across the diameter of a $12$-inch pizza when placed. If a total of $24$ circles of pepperoni are placed on this pizza without overlap, what fraction of the pizza is covered by pepperoni?

$\textbf{(A)}\ \frac 12 \qquad\textbf{(B)}\ \frac 23 \qquad\textbf{(C)}\ \frac 34 \qquad\textbf{(D)}\ \frac 56 \qquad\textbf{(E)}\ \frac 78$