Difference between revisions of "2013 AMC 12A Problems/Problem 1"
(Created page with "We know that the Area of a triangle is (bh)/2, so we can figure out that b=2A/h A=40 h=10 Therefore, b=80/10, which is 8, or E") |
|||
| Line 1: | Line 1: | ||
| − | We | + | We are given that the area of ∆ABE is 40, and that side AB is of length 10. |
| − | + | Side AB can be used as the height of ∆ABE. | |
| − | A= | + | Since A= (bh)/2, |
| − | |||
| − | + | 40=(10h)/2 | |
| − | + | ||
| + | and solving for h will give us 8, or E. | ||
Revision as of 20:37, 6 February 2013
We are given that the area of ∆ABE is 40, and that side AB is of length 10.
Side AB can be used as the height of ∆ABE.
Since A= (bh)/2,
40=(10h)/2
and solving for h will give us 8, or E.
