Difference between revisions of "2013 AMC 12A Problems/Problem 1"
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We are given that the area of ∆ABE is 40, and that side AB is of length 10. | We are given that the area of ∆ABE is 40, and that side AB is of length 10. | ||
| − | Side AB can be used as the height of ∆ABE. | + | Side AB can be used as the height of right ∆ABE. |
Since A= (bh)/2, | Since A= (bh)/2, | ||
Revision as of 20:50, 6 February 2013
We are given that the area of ∆ABE is 40, and that side AB is of length 10.
Side AB can be used as the height of right ∆ABE.
Since A= (bh)/2,
40=(10h)/2
and solving for h will give us 8, or E.
