Difference between revisions of "2013 AMC 12A Problems/Problem 4"
(Created page with "We can factor a 2^2012 out of the numerator and denominator to obtain ((2^2012)((2^2)+1))/((2^2012)((2^2)-1)) Both the (2^2012) terms cancel, so we get ((2^2)+1)/((2^2)-1) = ...") |
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| + | <math>\frac{2^{2014}+2^{2012}}{2^{2014}-2^{2012}}</math> | ||
| + | |||
We can factor a 2^2012 out of the numerator and denominator to obtain | We can factor a 2^2012 out of the numerator and denominator to obtain | ||
| − | + | <math>\frac{2^{2012}*(2^2+1)}{2^{2012}*(2^2-1)}</math> | |
Both the (2^2012) terms cancel, so we get | Both the (2^2012) terms cancel, so we get | ||
| − | + | <math>\frac{(2^2+1)}{(2^2-1)}=\frac{5}{3}</math>, which is C | |
Revision as of 21:17, 6 February 2013
We can factor a 2^2012 out of the numerator and denominator to obtain
Both the (2^2012) terms cancel, so we get
, which is C
