Difference between revisions of "2000 AMC 8 Problems/Problem 1"

(Solution)
Line 23: Line 23:
  
 
{{AMC8 box|year=2000|before=First<br />Question|num-a=2}}
 
{{AMC8 box|year=2000|before=First<br />Question|num-a=2}}
 +
{{MAA Notice}}

Revision as of 23:35, 4 July 2013

Problem

Aunt Anna is $42$ years old. Caitlin is $5$ years younger than Brianna, and Brianna is half as old as Aunt Anna. How old is Caitlin?

$\mathrm{(A)}\ 15 \qquad \mathrm{(B)}\ 16 \qquad \mathrm{(C)}\ 17 \qquad \mathrm{(D)}\ 21 \qquad \mathrm{(E)}\ 37$

Solution

If Brianna is half as old as Aunt Anna, then Briana is $\frac{42}{2}$ years old, or $21$ years old.

If Caitlin is $5$ years younger than Briana, she is $21-5$ years old, or $16$.

So, the answer is $\boxed{B}$

See Also

2000 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
First
Question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png