Difference between revisions of "1951 AHSME Problems/Problem 41"
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==Problem== | ==Problem== | ||
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+ | The formula expressing the relationship between <math>x</math> and <math>y</math> in the table is: | ||
+ | <cmath> | ||
+ | |||
+ | <math> \textbf{(A)}\ y = 2x-4\qquad\textbf{(B)}\ y = x^{2}-3x+2\qquad\textbf{(C)}\ y = x^{3}-3x^{2}+2x</math> | ||
+ | <math> \textbf{(D)}\ y = x^{2}-4x\qquad\textbf{(E)}\ y = x^{2}-4 </math> | ||
+ | |||
==Solution== | ==Solution== | ||
− | + | Just plug the <math>x,y</math> pair <math>(6,20)</math> into each of the 5 answer choices: | |
+ | |||
+ | (A): <math>2(6)-4=8\ne20</math> | ||
+ | |||
+ | (B): <math>6^2-3(6)+2=20</math> | ||
+ | |||
+ | (C): <math>6^3-3(6^2)+2(6)=120\ne20</math> | ||
+ | |||
+ | (D): <math>6^2-4(6)=12\ne20</math> | ||
+ | |||
+ | (E): <math>6^2-4=32\ne20</math> | ||
+ | |||
+ | The only one that works is <math>\boxed{\textbf{(B)}}</math>. | ||
+ | |||
== See Also == | == See Also == | ||
{{AHSME 50p box|year=1951|num-b=40|num-a=42}} | {{AHSME 50p box|year=1951|num-b=40|num-a=42}} |
Latest revision as of 10:14, 19 April 2014
Problem
The formula expressing the relationship between and in the table is:
Solution
Just plug the pair into each of the 5 answer choices:
(A):
(B):
(C):
(D):
(E):
The only one that works is .
See Also
1951 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 40 |
Followed by Problem 42 | |
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All AHSME Problems and Solutions |
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