Difference between revisions of "2003 AMC 10A Problems/Problem 16"
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<math>3^{2003}=(3^{4})^{500}\cdot3^{3}\equiv1^{500}\cdot27\equiv7\pmod{10}</math> | <math>3^{2003}=(3^{4})^{500}\cdot3^{3}\equiv1^{500}\cdot27\equiv7\pmod{10}</math> | ||
− | Therefore, the units digit is <math>7 \Rightarrow C</math> | + | Therefore, the units digit is <math>7 \Rightarrow\boxed{\mathrm{(C)}\ 7}</math> |
== See Also == | == See Also == |
Revision as of 22:42, 16 July 2014
Problem
What is the units digit of ?
Solution
Since :
Therefore, the units digit is
See Also
2003 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 15 |
Followed by Problem 17 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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