Difference between revisions of "2004 AMC 10A Problems/Problem 1"
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==Solution== | ==Solution== | ||
| − | There are 6 people to split the <math>1500</math> dollars among, so each person must raise <math>\frac{1500}6=250</math> dollars. <math>\Rightarrow\mathrm{( | + | There are 6 people to split the <math>1500</math> dollars among, so each person must raise <math>\frac{1500}6=250</math> dollars. <math>\Rightarrow\boxed{\mathrm{(B)}\ 250}</math> |
== See also == | == See also == | ||
Revision as of 17:12, 20 July 2014
Problem
You and five friends need to raise 
dollars in donations for a charity, dividing the fundraising equally. How many dollars will each of you need to raise?
Solution
There are 6 people to split the dollars among, so each person must raise 
dollars. 
See also
| 2004 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
