Difference between revisions of "1969 AHSME Problems/Problem 15"
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[[Category: Introductory Geometry Problems]] | [[Category: Introductory Geometry Problems]] | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 17:01, 30 September 2014
Problem
In a circle with center 
and radius 
, chord 
is drawn with length equal to (units). From , a perpendicular to meets at 
. From a perpendicular to 
meets at 
. In terms of the area of triangle 
, in appropriate square units, is:
Solution
See also
| 1969 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 14 |
Followed by Problem 16 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
