Difference between revisions of "1987 USAMO Problems/Problem 1"
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Now we relize <math>(m+1)^2</math> is a perfect square so <math>m(m-8)</math> has to be one too. | Now we relize <math>(m+1)^2</math> is a perfect square so <math>m(m-8)</math> has to be one too. | ||
<math>m</math> cannot be within <math>0<m<8</math> mecouse that makes <math>m(m-8)</math> less then <math>0</math>. | <math>m</math> cannot be within <math>0<m<8</math> mecouse that makes <math>m(m-8)</math> less then <math>0</math>. | ||
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Revision as of 10:24, 20 December 2015
By expanding we get From this the two cancel and you get: We can divide by (nonzero). We get: We can now factor the equation into: From here We get the discriminant: We factor: Now we relize is a perfect square so has to be one too. cannot be within mecouse that makes less then . .....