Difference between revisions of "2006 AMC 12A Problems/Problem 3"
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== Solution == | == Solution == | ||
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| + | Let <math>m</math> be Mary's age. Then <math>\frac{m}{30}=\frac{3}{5}</math>. Solving for <math>m</math>, we obtain <math>m=18</math>. The answer is B. | ||
== See also == | == See also == | ||
* [[2006 AMC 12A Problems]] | * [[2006 AMC 12A Problems]] | ||
Revision as of 21:06, 11 July 2006
Problem
The ratio of Mary's age to Alice's age is 
. Alice is 
years old. How old is Mary?
Solution
Let 
be Mary's age. Then 
. Solving for , we obtain 
. The answer is B.
