Difference between revisions of "2016 AMC 10B Problems/Problem 1"

Revision as of 09:20, 21 February 2016

What is the value of $\frac{2a^{-1}+\frac{a^{-1}}{2}}{a}$ when $a= \frac{1}{2}$ ?

$\textbf{(A)}\ 1\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ \frac{5}{2}\qquad\textbf{(D)}\ 10\qquad\textbf{(E)}\ 20$

$\frac{\frac{1}{a}*(2+\frac{1}{2})}{a}$ then becomes $\frac{\frac{5}{2}}{a^{2}}$ which is equal to $\frac{5}{2}*2^{2}$ = ${(D)}$

Solution by ngeorge

@@ Line 10: / Line 10: @@
 ==Solution==
-<math>\frac{frac{1}{a}*(2+frac{1}{2})}{a}</math> then becomes <math>frac{frac{5}{2}}{a^{2}}</math> which is equal to <math>frac{5}{2}*2^{2}</math> = <math>{(D)}</math>
+<math>\frac{\frac{1}{a}*(2+\frac{1}{2})}{a}</math> then becomes <math>\frac{\frac{5}{2}}{a^{2}}</math> which is equal to <math>\frac{5}{2}*2^{2}</math> = <math>{(D)}</math>
 Solution by ngeorge