Difference between revisions of "Proofs"

(Quadratic Formula)
(Quadratic Formula)
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Simplifying, we see
 
Simplifying, we see
 
<cmath>\boxed{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}</cmath>
 
<cmath>\boxed{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}</cmath>
 
-Designerd
 

Revision as of 22:37, 29 August 2016

Quadratic Formula

Let $ax^2+bx+c=0$. Then \[x^2+\frac{b}{a}x+\frac{c}{a}=0\] Completing the square, we get \[\left(x+\frac{b}{2a}\right)^2 +~ \frac{b^2-4ac}{4a^2}=0 \Rightarrow x~+~\frac{b}{2a}=\pm\sqrt{\frac{b^2-4ac}{4a^2}}=\frac{\pm \sqrt{b^2-4ac}}{2a}\] Simplifying, we see \[\boxed{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\]