Difference between revisions of "University of South Carolina High School Math Contest/1993 Exam/Problem 29"
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== Problem == | == Problem == | ||
+ | If the sides of a triangle have lengths 2, 3, and 4, what is the radius of the circle circumscribing the triangle? | ||
− | <center><math> \mathrm{(A) \ } \qquad \mathrm{(B) \ } \qquad \mathrm{(C) \ } \qquad \mathrm{(D) \ } \qquad \mathrm{(E) \ } </math></center> | + | <center><math> |
+ | \mathrm{(A) \ } 2 | ||
+ | \qquad \mathrm{(B) \ } 8/\sqrt{15} | ||
+ | \qquad \mathrm{(C) \ } 5/2 | ||
+ | \qquad \mathrm{(D) \ } \sqrt{6} | ||
+ | \qquad \mathrm{(E) \ } (\sqrt{6} + 1)/2 | ||
+ | </math></center> | ||
== Solution == | == Solution == | ||
+ | Using [[Heron's Formula]] and <math>R=\frac{abc}{4A}</math>, the answer is <math>\frac{8}{\sqrt{15}}</math>. | ||
== See also == | == See also == | ||
* [[University of South Carolina High School Math Contest/1993 Exam]] | * [[University of South Carolina High School Math Contest/1993 Exam]] |
Revision as of 19:18, 22 July 2006
Problem
If the sides of a triangle have lengths 2, 3, and 4, what is the radius of the circle circumscribing the triangle?
Solution
Using Heron's Formula and , the answer is .