Difference between revisions of "1990 AJHSME Problems/Problem 13"
m (→Solution) |
m (→Solution) |
||
Line 9: | Line 9: | ||
After the first ounce, there are <math>3.5</math> ounces left. Thus, it is required to pay for <math>3</math> ounces and then the extra half. | After the first ounce, there are <math>3.5</math> ounces left. Thus, it is required to pay for <math>3</math> ounces and then the extra half. | ||
− | The total price is <math>30+3.5\times 22=107</math> cents, which is choice <math>\boxed{\textbf{(B)}~1.07~\textbf{dollars}}</math>. | + | The total price is <math>30+3.5\times 22=107</math> cents, which is choice <math>\boxed{\textbf{(B)}~\mathbf{1.07}~\textbf{dollars}}</math>. |
==See Also== | ==See Also== |
Revision as of 22:51, 13 November 2016
Problem
One proposal for new postage rates for a letter was cents for the first ounce and cents for each additional ounce (or fraction of an ounce). The postage for a letter weighing ounces was
Solution
After the first ounce, there are ounces left. Thus, it is required to pay for ounces and then the extra half.
The total price is cents, which is choice .
See Also
1990 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 12 |
Followed by Problem 14 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.