Difference between revisions of "University of South Carolina High School Math Contest/1993 Exam/Problem 15"
Line 10: | Line 10: | ||
== Solution == | == Solution == | ||
− | + | ---- | |
− | * [[University of South Carolina High School Math Contest/1993 Exam]] | + | |
+ | * [[University of South Carolina High School Math Contest/1993 Exam/Problem 14|Previous Problem]] | ||
+ | * [[University of South Carolina High School Math Contest/1993 Exam/Problem 16|Next Problem]] | ||
+ | * [[University of South Carolina High School Math Contest/1993 Exam|Back to Exam]] | ||
[[Category:Intermediate Number Theory Problems]] | [[Category:Intermediate Number Theory Problems]] |
Revision as of 12:17, 23 July 2006
Problem
If we express the sum
![$\frac 1{3\cdot 5\cdot 7\cdot 11} + \frac 1{3\cdot 5\cdot 7\cdot 13} + \frac 1{3\cdot 5\cdot 11\cdot 13} + \frac 1{3\cdot 7\cdot 11\cdot 13} + \frac 1{5\cdot 7\cdot 11\cdot 13}$](http://latex.artofproblemsolving.com/c/f/0/cf021ead1590554d4996161c2d950d3c7f447e08.png)
as a rational number in reduced form, then the denominator will be
![$\mathrm{(A) \ }15015 \qquad \mathrm{(B) \ }5005 \qquad \mathrm{(C) \ }455 \qquad \mathrm{(D) \ }385 \qquad \mathrm{(E) \ }91$](http://latex.artofproblemsolving.com/8/c/3/8c3fe4240270899d2fdd51fbf04d42974d3c2c43.png)