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Difference between revisions of "2018 AIME I Problems/Problem 1"
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A three-dimensional rectangular box with dimensions <math>X</math>, <math>Y</math>, and <math>Z</math> has faces whose surface areas are <math>1746</math>, <math>1746</math>, <math>1854</math>, <math>1854</math>, <math>9991</math>, and <math>9991</math> square units. What is <math>X</math> + <math>Y</math> + <math>Z</math>?
 
A three-dimensional rectangular box with dimensions <math>X</math>, <math>Y</math>, and <math>Z</math> has faces whose surface areas are <math>1746</math>, <math>1746</math>, <math>1854</math>, <math>1854</math>, <math>9991</math>, and <math>9991</math> square units. What is <math>X</math> + <math>Y</math> + <math>Z</math>?
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Solution 1(Currently Only the Answer is present, someone must give the solution)
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The answer is <math>\boxed{218}</math>.

Revision as of 20:59, 28 February 2018

A three-dimensional rectangular box with dimensions $X$, $Y$, and $Z$ has faces whose surface areas are $1746$, $1746$, $1854$, $1854$, $9991$, and $9991$ square units. What is $X$ + $Y$ + $Z$?


Solution 1(Currently Only the Answer is present, someone must give the solution)

The answer is $\boxed{218}$.

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