1955 AHSME Problems/Problem 6
A merchant buys a number of oranges at for
cents and an equal number at
for
cents. To "break even" he must sell all at:
Since we are buying at for
cents and
for
cents, let's assume that together, we are buying 15 oranges.
That means that we are getting a total of
oranges for
cents.
That comes to a total of
oranges for
cents.
=
. This leads us to
for
cents which is
and we are done.
-Brudder