2020 CIME I Problems/Problem 7
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Problem 7
For every positive integer , define Suppose that the sum can be expressed as for relatively prime integers and . Find the remainder when is divided by .
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it. Notice that the product of first 2n+1 odd numbers = (2n+2)! / ((2^n+2)*(n+1)!) ; substituting this for f(n) gives the answer
See also
2020 CIME I (Problems • Answer Key • Resources) | ||
Preceded by Problem 6 |
Followed by Problem 8 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All CIME Problems and Solutions |
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