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2021 AMC 10A Problems/Problem 1

Revision as of 13:19, 11 February 2021 by Happykeeper (talk | contribs) (→‎Solution)

Problem

What is the value of \[(2^2-2)-(3^2-3)+(4^2-4)\]

$\textbf{(A) } 1 \qquad\textbf{(B) } 2 \qquad\textbf{(C) } 5 \qquad\textbf{(D) } 8 \qquad\textbf{(E) } 12$

Solution

$(4-2)-(9-3)+(16-4)=2-6+12=8.$ This corresponds to $\boxed{\text{D}}$

-happykeeper

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