2021 Fall AMC 12B Problems/Problem 9
Problem
Triangle is equilateral with side length . Suppose that is the center of the inscribed circle of this triangle. What is the area of the circle passing through , , and ?
Solution 1 (Cosine Rule)
Construct the circle that passes through , , and , centered at .
Then connect , and notice that is the perpendicular bisector of . Let the intersection of with be .
Also notice that and are the angle bisectors of angle $\angleBAC$ (Error compiling LaTeX. Unknown error_msg) and $\angleBCA$ (Error compiling LaTeX. Unknown error_msg) respectively. We then deduce .
Consider another point on Circle opposite to point .
As an inscribed quadrilateral of Circle , $\angleAMC=180^\circ-120^\circ=60^\circ$ (Error compiling LaTeX. Unknown error_msg).
Afterward, deduce that $\angleAXC=2·\angleAMC=120^\circ$ (Error compiling LaTeX. Unknown error_msg).
By the Cosine Rule, we have the equation: (where is the radius of circle )
The area is therefore .
~Wilhelm Z