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2023 AMC 8 Problems/Problem 19

Revision as of 18:32, 24 January 2023 by Starleague (talk | contribs)
By AA~ similarity triangle we can find the ratio of the area of big: small —> $\frac{9}{4}$ then there are a relative $5$ for the $3$ trapezoids combines. For $1$ trapezoid it is a relative $53$ so now the ratio is $\frac{5}{\frac{3}{4}}$ which can simplify to $\boxed{\text(C) \frac{5}{12}}$


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