2023 AMC 10A Problems/Problem 9

Revision as of 19:11, 9 November 2023 by Puck 0 (talk | contribs) (Solution)

A digital display shows the current date as an $8$-digit integer consisting of a $4$-digit year, followed by a $2$-digit month, followed by a $2$-digit date within the month. For example, Arbor Day this year is displayed as 20230428. For how many dates in $2023$ will each digit appear an even number of times in the 8-digital display for that date?

$\textbf{(A)}~5\qquad\textbf{(B)}~6\qquad\textbf{(C)}~7\qquad\textbf{(D)}~8\qquad\textbf{(E)}~9$

Solution

Do careful casework by each month. In the month and the date, we need a $0$, a $3$, and two digits repeated. After the case work, we get $9$, meaning the answer $\boxed{E}$ For those who are wondering, the numbers are: 20230113, 20230131, 20230223, 20230311, 20230322, 20231013, 20231031, 20231103, 20231130.

Video Solution 1 by OmegaLearn

https://youtu.be/xguAy0PV7EA