1986 AJHSME Problems/Problem 1

Revision as of 17:57, 24 January 2009 by Waffle (talk | contribs)

Problem

In July 1861, $366$ inches of rain fell in Cherrapunji, India. What was the average rainfall in inches per hour during that month?

$\text{(A)}\ \frac{366}{31\times 24}$

$\text{(B)}\ \frac{366\times 31}{24}$

$\text{(C)}\ \frac{366\times 24}{31}$

$\text{(D)}\ \frac{31\times 24}{366}$

$\text{(E)}\  366\times 31\times 24$

Solution

We can express the number of inches of rain in a ratio, $\frac{366 inches}{1 month}$. We need to find to find the number of hours, but first we need to find the number of days. We know there are 31 days in July, so we get...

$\frac{366 inches}{1 month} \times \frac{1 month}{31 days}$

We know there are 24 hours in a day, so we get...

$\frac{366 inches}{1 month} \times \frac{1 month}{31 days} \times \frac{1 day}{24 hours}$

And simplifying gets us...

$\frac{366 inches}{31 \times 24 hours}$, which is A.

Note that in the simplifying step, we noted that the month and day units cancel, leaving us with only inches per hour.

See Also

1986 AJHSME Problems