1986 AJHSME Problems/Problem 13
Problem
The perimeter of the polygon shown is
Solution
Solution 1
For the segments parallel to the side with side length 8, let's call those two segments and , the longer segment being , the shorter one being .
For the segments parallel to the side with side length 6, let's call those two segments and , the longer segment being , the shorter one being .
So the perimeter of the polygon would be...
Note that , and .
Now we plug those in:
28 is .
Solution 2
The perimeter of the requested region is the same as the perimeter of the rectangle with the dashed portion. This makes the answer
See Also
1986 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 12 |
Followed by Problem 14 | |
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All AJHSME/AMC 8 Problems and Solutions |