1991 AHSME Problems/Problem 1
Revision as of 12:51, 22 July 2014 by MathLearner01 (talk | contribs) (Added solution and changed format of answer choices.)
Problem
If for any three distinct numbers ,
, and
we define
, then
is
Solution
If we plug in as
,
as
, and
as
in the expression
, then we get
, which is choice
.
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