2012 AMC 10B Problems/Problem 9
Problem 9
Two integers have a sum of 26. When two more integers are added to the first two integers the sum is 41. Finally when two more integers are added to the sum of the previous four integers the sum is 57. What is the minimum number of even integers among the 6 integers?
$\textbf{(A)}\ 1\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 3\qquad\textbf{(D)}\ 4\qquad\textbf{(E)}\5$ (Error compiling LaTeX. Unknown error_msg)
Solution
Out of the first two integers, it's possible for both to be even: for example, 
But the next two integers, when added, increase the sum by 
which is odd, so one of them must be odd: for example, 
Finally, the next two integers increase the sum by 
which is even, so we can have both be even: for example, 
Therefore, 
is the minimum number of integers that must be odd.
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