2014 USAJMO Problems

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Day 1

Problem 1

Let $a$, $b$, $c$ be real numbers greater than or equal to $1$. Prove that \[\min{\left (\frac{10a^2-5a+1}{b^2-5b+1},\frac{10b^2-5b+1}{c^2-5c+10},\frac{10c^2-5c+1}{a^2-5a+10}\right )}\leq abc\] Solution

Problem 2

Solution

Problem 3

Solution

Day 2

Problem 4

Solution

Problem 5

Solution

Problem 6

Solution