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1975 IMO Problems/Problem 3

Revision as of 12:28, 20 October 2013 by Elvis (talk | contribs) (Created page with "On the sides of an arbitrary triangle ABC; triangles ABR;BCP;CAQ are constructed externally with CBP = CAQ = 45°; BCP = ACQ = 30°; ABR = BAR = 15°: Prove that QRP = 90° and Q...")
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On the sides of an arbitrary triangle ABC; triangles ABR;BCP;CAQ are constructed externally with CBP = CAQ = 45°; BCP = ACQ = 30°; ABR = BAR = 15°: Prove that QRP = 90° and QR = RP:

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