1978 AHSME Problems/Problem 15
Revision as of 02:56, 13 February 2021 by Justinlee2017 (talk | contribs) (Created page with "==Solution== Squaring the equation, we get <cmath>\sin ^2 x + \cos ^2 x + 2 \sin x \cos x = \frac{1}{25} =\Rrightarrow 2\sin x \cos x = -\frac{24}{25} \Rrightarrow \sin x \cos...")
Solution
Squaring the equation, we get
Recall that
, so
We can now solve for the values of
and
Since
, we have
~JustinLee2017