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2021 JMPSC Accuracy Problems/Problem 4

Revision as of 21:09, 10 July 2021 by Bradygho (talk | contribs) (→‎Solution)

Problem

If $\frac{x+2}{6}$ is its own reciprocal, find the product of all possible values of $x.$

Solution

From the problem, we know that \[\frac{x+2}{6} = \frac{6}{x+2}\] \[(x+2)^2 = 6^2\] \[x^2+ 4x + 4 = 36\] \[x^2 + 4x - 32 = 0\] \[(x-8)(x+4) = 0\]

Thus, $x = 8$ or $x = -4$. Our answer is $8 \cdot(-4)=\boxed{-32}$

~Bradygho

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