2021 JMPSC Invitationals Problems/Problem 1
Revision as of 20:04, 11 July 2021 by Geometry285 (talk | contribs)
Contents
Problem
The equation where is some constant, has as a solution. What is the other solution?
Solution
Since must be a solution, must be true. Therefore, . We plug this back in to the original quadratic to get . We can solve this quadratic to get . We are asked to find the 2nd solution so our answer is
~Grisham
Solution 2
Plug to get , so , or , meaning the other solution is ~Geometry285
See also
- Other 2021 JMPSC Invitationals Problems
- 2021 JMPSC Invitationals Answer Key
- All JMPSC Problems and Solutions
The problems on this page are copyrighted by the Junior Mathematicians' Problem Solving Competition.