2004 AMC 8 Problems/Problem 12

Revision as of 18:48, 18 July 2019 by Goldenn (talk | contribs) (Problem)

Problem

Niki usually leaves her cell phone on. If her cell phone is on but she is not actually using it, the battery will last for $24$ hours. If she is using it constantly, the battery will last for only $3$ hours. Since the last recharge, her phone has been on $9$ hours, and during that time she has used it for $60$ minutes. If she doesn’t use it any more but leaves the phone on, how many more hours will the battery last?

$\textbf{(A)}\ 7 \qquad \textbf{(B)}\ 8 \qquad \textbf{(C)}\ 11 \qquad \textbf{(D)}\ 14 \qquad \textbf{(E)}\ 15$

Solution

When not being used, the cell phone uses up $1/24$ of its battery per hour. When being used, the cell phone uses up $1/3$ of its battery per hour. Since Niki's phone has been on for $9$ hours, of those $8$ simply on and $1$ being used to talk, $8(1/24) + 1(1/3) = 2/3$ of its battery has been used up. To drain the remaining $1/3$ the phone can last for $\frac{1/3}{1/24}=\boxed{\textbf{(B)}\ 8}$ more hours without being used.

See Also

2004 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 11
Followed by
Problem 13
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png