2023 AMC 12A Problems/Problem 7

Revision as of 19:58, 9 November 2023 by D code (talk | contribs) (Solution 1)

Problem

Janet rolls a standard $6$-sided die $4$ times and keeps a running total of the numbers she rolls. What is the probability that at some point, her running total will equal $3$?

Solution 1

There are $4$ cases where her running total can equal $3$: 1. She rolled $1$ for three times consecutively from the beginning. Probability: $\frac{1}{6^3} = \frac{1}{216}$ 2. She rolled a $1$, then $2$. Probability: $\frac{1}{6^2} = \frac{1}{36}$ 3. She rolled a $2$, then $1$. Probability: $\frac{1}{6^2} = \frac{1}{36}$ 4. She rolled a $3$ at the beginning. Probability: $\frac{1}{6}$

Add them together to get $\boxed{\textbf{(B)} \frac{49}{216}}.$

~d_code