2024 AMC 8 Problems/Problem 24
Contents
- 1 Problem
- 2 Solution 1
- 3 Video Solution by Power Solve (easy to understand)
- 4 Video Solution 1 by Math-X (First understand the problem!!!)
- 5 2 minute solve (fast) by MegaMath
- 6 Video Solution by OmegaLearn.org
- 7 Video Solution by SpreadTheMathLove
- 8 Video Solution by CosineMethod [🔥Fast and Easy🔥]
- 9 See Also
Problem
Jean has made a piece of stained glass art in the shape of two mountains, as shown in the figure below. One mountain peak is 
feet high while the other peak is 
feet high. Each peak forms a 
angle, and the straight sides form a 
angle with the ground. The artwork has an area of 
square feet. The sides of the mountain meet at an intersection point near the center of the artwork, 
feet above the ground. What is the value of 
![[asy] unitsize(.3cm); filldraw((0,0)--(8,8)--(11,5)--(18,12)--(30,0)--cycle,gray(0.7),linewidth(1)); draw((-1,0)--(-1,8),linewidth(.75)); draw((-1.4,0)--(-.6,0),linewidth(.75)); draw((-1.4,8)--(-.6,8),linewidth(.75)); label("$8$",(-1,4),W); label("$12$",(31,6),E); draw((-1,8)--(8,8),dashed); draw((31,0)--(31,12),linewidth(.75)); draw((30.6,0)--(31.4,0),linewidth(.75)); draw((30.6,12)--(31.4,12),linewidth(.75)); draw((31,12)--(18,12),dashed); label("$45^{\circ}$",(.75,0),NE,fontsize(10pt)); label("$45^{\circ}$",(29.25,0),NW,fontsize(10pt)); draw((8,8)--(7.5,7.5)--(8,7)--(8.5,7.5)--cycle); draw((18,12)--(17.5,11.5)--(18,11)--(18.5,11.5)--cycle); draw((11,5)--(11,0),dashed); label("$h$",(11,2.5),E); [/asy]](http://latex.artofproblemsolving.com/0/6/2/062be4008fc995e68ebbe56afa0a90b07160a7d6.png)
Solution 1
Extend the "inner part" of the mountain so that the image is two right triangles that overlap in a third right triangle. The side length of the largest right triangle is 
which means its area is 
Similarly, the area of the second largest right triangle is 
(the side length is 
), and the area of the overlap triangle is 
(the side length is 
) Thus,
![\[144+64-h^2=183,\]](http://latex.artofproblemsolving.com/d/a/3/da33465ebae23a898b76506cd66992f6ff48089f.png)
which means that the answer is 
~BS2012
Video Solution by Power Solve (easy to understand)
https://www.youtube.com/watch?v=PlMGNmWIkBg
Video Solution 1 by Math-X (First understand the problem!!!)
https://www.youtube.com/watch?v=j6rzEkESmT4
~Math-X
2 minute solve (fast) by MegaMath
https://www.youtube.com/watch?v=hUh0hux3xuU
Video Solution by OmegaLearn.org
Video Solution by SpreadTheMathLove
https://www.youtube.com/watch?v=RiSt6_WLfrM
Video Solution by CosineMethod [🔥Fast and Easy🔥]
https://www.youtube.com/watch?v=H5Pq8mf-OVk
See Also
| 2024 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 23 |
Followed by Problem 25 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
