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1986 AJHSME Problems/Problem 4

Revision as of 16:38, 18 January 2009 by 5849206328x (talk | contribs) (→‎See Also)

Problem

The product $(1.8)(40.3+.07)$ is closest to

$\text{(A)}\ 7 \qquad \text{(B)}\ 42 \qquad \text{(C)}\ 74 \qquad \text{(D)}\ 84 \qquad \text{(E)}\ 737$

Solution

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See Also

1986 AJHSME Problems

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