1999 AMC 8 Problems/Problem 23

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Since the squares have side length $3$, the area of the entire square is $9$.

The segments divide the square into 3 equal parts, so the area of each part is $3$.

The base of a triangle is $3$, so the height must be $2$.

$3-2=1$.

$CM=\sqrt {3^2+2^2$ (Error compiling LaTeX. Unknown error_msg)} = $\sqrt 13$