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2005 AMC 10B Problems/Problem 9

Revision as of 23:48, 31 October 2009 by Zheng (talk | contribs)

An odd sum requires either that the first die is even and the second is odd or that the first die is odd and the second is even. The probability is $(1/3*1/3)+(2/3*2/3)$=$1/9+4/9=5/9$=D

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