1969 AHSME Problems/Problem 20

Revision as of 21:50, 30 September 2014 by Timneh (talk | contribs) (Created page with "== Problem == Let <math>P</math> equal the product of 3,659,893,456,789,325,678 and 342,973,489,379,256. The number of digits in <math>P</math> is: <math>\text{(A) } 36\quad \t...")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Problem

Let $P$ equal the product of 3,659,893,456,789,325,678 and 342,973,489,379,256. The number of digits in $P$ is:

$\text{(A) } 36\quad \text{(B) } 35\quad \text{(C) } 34\quad \text{(D) } 33\quad \text{(E) } 32$

Solution

$\fbox{C}$

See also

1969 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 19
Followed by
Problem 21
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png