University of South Carolina High School Math Contest/1993 Exam/Problem 23
Problem
The relation between the sets
![$M = \{ 12 m + 8 n + 4 l: m,n,l \rm{ \ are \ } \rm{integers}\}$](http://latex.artofproblemsolving.com/8/5/d/85df64d0e050415fe93cde4d432162aea5546227.png)
and
![$N= \{ 20 p + 16q + 12r: p,q,r \rm{ \ are \ } \rm{integers}\}$](http://latex.artofproblemsolving.com/a/1/3/a137cf2604fac5c5ae08b650f9bc1db1f29575e2.png)
is
![$\mathrm{(A) \ } M\subset N \qquad \mathrm{(B) \ } N\subset M \qquad \mathrm{(C) \ } M\cup N = \{0\} \qquad \mathrm{(D) \ }60244 \rm{ \ is \ } \rm{in \ } M \rm{ \ but \ } \rm{not \ } \rm{in \ } N \qquad \mathrm{(E) \ } M=N$](http://latex.artofproblemsolving.com/a/6/6/a66382490281eeb37a27763b42602a93e82b8126.png)
Solution
Any integer that can be created through can be created through
and vice versa. Thus
.
The relation between the sets
and
is
Any integer that can be created through can be created through
and vice versa. Thus
.
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