Mock AIME 5 Pre 2005 Problems/Problem 12

Revision as of 15:55, 18 August 2013 by MSTang (talk | contribs) (Solution)

Problem

Let $m = 101^4 + 256$. Find the sum of the digits of $m$.

Solution

By the binomial theorem,

\begin{aligned} 101^4 + 256 &= (100 + 1)^4 + 256 \\ &= (100^4 + 4\cdot 100^3 + 6 \cdot 100^2 + 4 \cdot 100 + 1) + 256 \\  &= 104060401 + 256 = 104060657, \end{aligned} (Error compiling LaTeX. Unknown error_msg)

and so the sum of the digits is $1+4+6+6+5+7 = \boxed{29}.$

See also

Mock AIME 5 Pre 2005 (Problems, Source)
Preceded by
Problem 11
Followed by
Problem 13
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